Sunday, May 24, 2015
may 24
Sunday, May 17, 2015
may 17
Wednesday, May 13, 2015
may 10
- Nim (or Nim2, where one is allowed to take away 1 or 2 stones, other Nims are possible) - the complete solution is easy: if one faces the pile with the number of stones there divisible by three, one loses given the opponent plays wisely, and wins otherwise. We established that using the recursion, an awfully useful trick.
- This led to the question, how you determine divisibility by three? The sum of digits trick helps...
Draw projections of some shapes- Split into 3 parts led to the question: can one tile the plane with these pentaminos?
Homework:
- One can tile (cover without overlaps or holes) the whole plane with the r pentaminos, for example as shown below:
Now, can you tile the whole plane with T-pentaminos? Or with y's? or z's?
- Is 198407392 divisible by 3? What about 38002978643001?
- Who wins the game of Nim3 starting with the pile of 101 stones?
Saturday, May 2, 2015
may 3
- We finish the three different coins puzzle (how to order them with fewest weighings on a scale)
- We'll work on the Nim game: what is the best possible strategy? Who wins if one starts with 100 stones?
- Vectors! we will add more than one vector; and see what kind of configurations sum up to zero...
- We play more of the "pick a symbol" game...
- Time permitting, we'll talk about splitting the payment for rice bowl...
Homework!
- We established the pattern of whether the person wins or loses facing a pile in the Nim game - one wins if the pile has 1 or 2 or 4 or 5 stones; loses with 3 or 6...
1 2 3 4 5 6 7 ... ... 99 100 W W L W W L W ... ... ? ? - Roman numerals strike again: Find CIX+LXXI-XL=?
- Split into three equal shapes:
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